Question

what is the net ionic equation for the reaction?
h₃po₄ + 3koh → k₃po₄ + 3h₂o
○ 3k⁺ + 3oh⁻ → 3koh
○ po₄³⁻ + oh⁻ → h₃po₄
○ h⁺ + oh⁻ → h₂o
○ 3h⁺ + 3k⁺ → 3kh
○ 3k⁺ + po₄³⁻ → k₃po₄

Explanation:

Step1: Write the complete ionic equation

$$\ce{H3PO4(aq) + 3K+(aq) + 3OH-(aq) -> 3K+(aq) + PO4^{3 - }(aq) + 3H2O(l)}$$

Step2: Cancel the spectator ions ($\ce{K+}$)

After canceling $\ce{3K+}$ on both sides, we get the net ionic equation.

Answer:

$\ce{H+ + OH- -> H2O}$ (Note: $\ce{H3PO4}$ is a weak acid, but in net - ionic equations for acid - base reactions, we can represent it as donating $\ce{H+}$ in a simplified sense for the purpose of showing the acid - base reaction core which is $\ce{H+}$ (from acid) reacting with $\ce{OH-}$ (from base) to form water. The actual full - fledged treatment of $\ce{H3PO4}$ ionization is more complex, but among the given options, this is the most appropriate as it represents the acid - base neutralization essence)