Question

what is the mole ratio of mg to mgcl₂? mg(s) + hcl(aq) → mgcl₂(aq) + h₂(g) 1 mol mg/ 2 mol mgcl₂ 2 mol mg/ 1 mol mgcl₂ 1 mol mg/ 1 mol mgcl₂ 2 mol mg/ 2 mol mgcl₂

Explanation:

Step1: Balance the chemical equation

$$\mathrm{Mg(s) + 2HCl(aq) ightarrow MgCl_2(aq) + H_2(g)}$$

Step2: Determine the mole ratio

From the balanced equation, the coefficient of $\mathrm{Mg}$ is $1$ and the coefficient of $\mathrm{MgCl_2}$ is $1$. So the mole ratio of $\mathrm{Mg}$ to $\mathrm{MgCl_2}$ is $\frac{1\space mol\space Mg}{1\space mol\space MgCl_2}$.

Answer:

$1\space mol\space Mg/1\space mol\space MgCl_2$ (the third option)