Question

what is the molar mass of the ionic compound mg3n2? mg3n2 = ? g/mol

Explanation:

Step1: Calculate the mass of Mg

There are 3 Mg atoms. Given the molar mass of Mg is \(24.31\frac{g}{mol}\), so the mass contribution of Mg is \(3\times24.31\frac{g}{mol}\).

$$3\times24.31 = 72.93\frac{g}{mol}$$

Step2: Calculate the mass of N

There are 2 N atoms. Given the molar mass of N is \(14.01\frac{g}{mol}\), so the mass contribution of N is \(2\times14.01\frac{g}{mol}\).

$$2\times14.01=28.02\frac{g}{mol}$$

Step3: Calculate the molar mass of \(Mg_3N_2\)

Add the mass contributions of Mg and N.

$$72.93 + 28.02=100.95\frac{g}{mol}$$

Answer:

\(100.95\frac{g}{mol}\)