Question

what is the molar mass of this compound? mn(so₃)₂ remember to round to the hundredths place from the periodic table. 135.01 g/mol 103.01 g/mol 215.08 g/mol 105.00 g/mol

Explanation:

Step1: Find molar mass of each element

• Manganese (\(Mn\)): \(54.94\space g/mol\)
• Sulfur (\(S\)): \(32.07\space g/mol\)
• Oxygen (\(O\)): \(16.00\space g/mol\)

Step2: Calculate molar mass of \(Mn(SO_{3})_{2}\)

• There is \(1\) \(Mn\) atom: \(1\times54.94 = 54.94\space g/mol\)
• There are \(2\) \(S\) atoms: \(2\times32.07=64.14\space g/mol\)
• There are \(6\) \(O\) atoms (\(2\times3\)): \(6\times16.00 = 96.00\space g/mol\)

Step3: Sum up the molar masses

$$54.94+64.14 + 96.00=215.08\space g/mol$$

Answer:

\(215.08\space g/mol\)