Question

1. what is the mathematical ratio of the volume of oxygen created to the volume of hydrogen created?

1:2
1:1
1:3
2:2

1. how does the mathematical ratio translate to relative amounts expressed in the balanced equation?

there are two moles of hydrogen gas and one mole of oxygen gas. this corresponds to the 2:1 ratio for the volume of gas produced.
each molecule of hydrogen gas reacts with one molecule of oxygen gas to produce water in a 1:1 ratio
the ratio refers only to the mass of the substances, not their volume or moles.
for every two moles of oxygen gas, four moles of hydrogen gas are required, showing a 4:2 ratio.

Explanation:

Question 6

Step1: Recall electrolysis of water

The balanced equation for water electrolysis is $2H_2O
ightarrow 2H_2 + O_2$. At same conditions, volume ratio of gases is equal to mole ratio.

Step2: Determine volume ratio

Moles of $O_2$: 1, moles of $H_2$: 2. So volume ratio (O₂:H₂) is 1:2.

The balanced equation for water electrolysis is $2H_2O
ightarrow 2H_2 + O_2$. Moles of $H_2$ is 2, moles of $O_2$ is 1. Volume ratio of gases (at same conditions) equals mole ratio. So the correct option explains that 2 moles of $H_2$ and 1 mole of $O_2$ give a 2:1 (or inverse 1:2 for O₂:H₂) volume ratio. The first option matches this: "There are two moles of hydrogen gas and one mole of oxygen gas. This corresponds to the 2:1 ratio for the volume of gas produced."

Answer:

1:2 (the option with "1:2")

Question 7