Question

what mass of cl₂ reacted when 0.243 g mg reacted completely to form 0.953 g mgcl₂? 1.196 g cl₂ 3.920 g cl₂ 0.710 g cl₂ 0.255 g cl₂

Explanation:

Step1: Use the law of conservation of mass

The law of conservation of mass states that in a chemical reaction, the mass of reactants equals the mass of products. Here, \(Mg + Cl_2
ightarrow MgCl_2\). So, \(m(Mg)+m(Cl_2)=m(MgCl_2)\)

Step2: Rearrange the formula to find \(m(Cl_2)\)

We can rewrite the formula as \(m(Cl_2)=m(MgCl_2)-m(Mg)\)

Substitute the given values: \(m(Mg) = 0.243g\) and \(m(MgCl_2)=0.953g\)

\(m(Cl_2)=0.953 - 0.243\)

\(m(Cl_2)=0.710g\)

Answer:

\(0.710g\ Cl_2\) (the third option)