Question

what is the mass of 2.5 x 10^24 atoms of ne? molar mass of ne = 20.18 g/mol 1 mole = 6.02 x 10^23 atoms 1.5 x 10^48 g ne 84 g ne 4.2 g ne 0.21 g ne

Explanation:

Step1: Calculate the number of moles

Use the formula \(n=\frac{N}{N_A}\), where \(N = 2.5\times10^{24}\) atoms (number of atoms of Ne) and \(N_A=6.02\times 10^{23}\text{ atoms/mol}\) (Avogadro's number).

$$n=\frac{2.5\times 10^{24}}{6.02\times 10^{23}}$$

$$n\approx4.153\space mol$$

Step2: Calculate the mass

Use the formula \(m = n\times M\), where \(n = 4.153\space mol\) (number of moles of Ne) and \(M = 20.18\space g/mol\) (molar mass of Ne).

$$m=4.153\times20.18$$

$$m\approx84\space g$$

Answer:

\(84\space g\space Ne\)