Question

what is the final concentration of 1,500. ml of a solution made from 200. ml of 18 m h₂so₄? ? m h₂so₄

Explanation:

Step1: Recall dilution formula

The dilution formula is \( M_1V_1 = M_2V_2 \), where \( M_1 \) is initial molarity, \( V_1 \) is initial volume, \( M_2 \) is final molarity, \( V_2 \) is final volume.
Here, \( M_1 = 18 \, M \), \( V_1 = 200. \, mL \), \( V_2 = 1500. \, mL \), find \( M_2 \).

Step2: Rearrange formula for \( M_2 \)

From \( M_1V_1 = M_2V_2 \), we get \( M_2=\frac{M_1V_1}{V_2} \).

Step3: Substitute values

Substitute \( M_1 = 18 \), \( V_1 = 200 \), \( V_2 = 1500 \) into the formula:
\( M_2=\frac{18 \times 200}{1500} \)

Step4: Calculate

\( 18\times200 = 3600 \), then \( \frac{3600}{1500}=2.4 \)

Answer:

\( 2.4 \)