Question

1. what is the empirical formula for the compound that has 46 grams of sodium, 64 grams of sulfur, and 48 grams of oxygen? options: na₂s₂o₂, na₃s₂o₂, na₃s₃o₃, na₂s₂o₃

Explanation:

Step1: Find moles of each element

Molar mass of Na = 23 g/mol, S = 32 g/mol, O = 16 g/mol.
Moles of Na: $\frac{46\ g}{23\ g/mol} = 2\ mol$
Moles of S: $\frac{64\ g}{32\ g/mol} = 2\ mol$
Moles of O: $\frac{48\ g}{16\ g/mol} = 3\ mol$

Step2: Determine the ratio

The mole ratio of Na : S : O is 2 : 2 : 3.

Answer:

$\boldsymbol{Na_2S_2O_3}$ (the fourth option: D. $Na_2S_2O_3$)