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Question
what element has the configuration 1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p³ br sc se as
Step1: Calculate the total number of electrons
The sum of the exponents in the electron configuration gives the number of electrons.
$$2 + 2+6 + 2+6 + 2+10 + 3=33$$
Step2: Relate the number of electrons to the atomic number
In a neutral atom, the number of electrons is equal to the atomic number. So the atomic number \(Z = 33\).
Step3: Identify the element
Looking at the periodic table, the element with atomic number \(33\) is Arsenic (\(As\)).
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