Question

in what block, group, and period on the periodic table can the atom with a \\(1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^{10} 4p^5\\) ground-state electron configuration be found?
p-block, group 7, and period 4
p-block, group 7, and period 5
p-block, group 7, and period 3

Explanation:

Identify the block from the configuration

The highest energy subshell being filled is \(4p^5\), which places the element in the p-block.

Determine the period number

The highest principal quantum number \(n\) in the configuration is \(4\) (from \(4s^2\) and \(4p^5\)), which corresponds to period 4.

Determine the group number

The valence shell configuration is \(4s^2 4p^5\), giving \(2 + 5 = 7\) valence electrons, which corresponds to Group 7A (or Group 17 in IUPAC notation, represented here as group 7).

Answer:

• (A) p-block, group 7, and period 4 (Correct answer)
• (B) p-block, group 7, and period 5
• (C) p-block, group 7, and period 3