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the vapor pressure of water at 80°c is 0.468 atm. calculate the vapor p…

Question

the vapor pressure of water at 80°c is 0.468 atm. calculate the vapor pressure in mmhg and torr. round each of your answers to 3 significant digits.

Explanation:

Step1: Recall conversion factor for atm to mmHg

We know that \( 1\ \text{atm} = 760\ \text{mmHg} \) and also \( 1\ \text{atm} = 760\ \text{torr} \) (since 1 mmHg = 1 torr).

Step2: Calculate vapor pressure in mmHg

To convert from atm to mmHg, we use the conversion factor. Multiply the given pressure in atm by 760 mmHg/atm.

$$ 0.468\ \text{atm} \times \frac{760\ \text{mmHg}}{1\ \text{atm}} = 0.468\times760\ \text{mmHg} $$
$$ 0.468\times760 = 355.68\ \text{mmHg} $$

Rounding to 3 significant digits, we get \( 356\ \text{mmHg} \).

Step3: Calculate vapor pressure in torr

Since \( 1\ \text{mmHg} = 1\ \text{torr} \), the pressure in torr will be the same as in mmHg after conversion. So using the same conversion factor (1 atm = 760 torr):

$$ 0.468\ \text{atm} \times \frac{760\ \text{torr}}{1\ \text{atm}} = 0.468\times760\ \text{torr} $$
$$ 0.468\times760 = 355.68\ \text{torr} $$

Rounding to 3 significant digits, we get \( 356\ \text{torr} \).

Answer:

Vapor pressure in mmHg: \( 356\ \text{mmHg} \)
Vapor pressure in torr: \( 356\ \text{torr} \)