Question

using the puzzle pieces provided (and by duplicating them), create three different ionic compounds that contain variable charge metals (options on previous slide). be sure to name each compound you create (remember those roman numerals we just talked about!)

Explanation:

Compound 2

Step1: Select ions

Choose \(Cu^{2+}\) (copper with a \(+ 2\) charge) and \(O^{2 -}\) (oxide ion).

Step2: Balance charges

The charge on \(Cu^{2+}\) is \(+2\) and on \(O^{2 -}\) is \(-2\). So, the ratio is \(1:1\).

Step3: Write formula

The formula is \(CuO\).

Step4: Name the compound

Using Roman numerals, the name is Copper(II) oxide.

Compound 3

Step1: Select ions

Choose \(Co^{3+}\) (cobalt with a \(+3\) charge) and \(Br^{-}\) (bromide ion).

Step2: Balance charges

The charge on \(Co^{3+}\) is \(+3\) and on \(Br^{-}\) is \(-1\). To balance, we need \(3\) \(Br^{-}\) ions for \(1\) \(Co^{3+}\) ion.

Step3: Write formula

The formula is \(CoBr_{3}\).

Step4: Name the compound

Using Roman numerals, the name is Cobalt(III) bromide.

Answer:

Compound 2:
Name: Copper(II) oxide
Formula: \(CuO\)

Compound 3:
Name: Cobalt(III) bromide
Formula: \(CoBr_{3}\)