Question

use the standard normal distribution table to determine the percent of data between \\(z = 0.35\\) and \\(z = 1.46\\).

click here to view page 1 of the standard normal distribution table.
click here to view page 2 of the standard normal distribution table.

the percent of data between \\(z = 0.35\\) and \\(z = 1.46\\) is \\(\box\\)%.
(round to two decimal places as needed.)

Explanation:

Find cumulative area for z = 1.46

Using the Standard Normal Table knowledge point

$$ P(Z < 1.46) = 0.9279 $$

Find cumulative area for z = 0.35

Using the Standard Normal Table knowledge point

$$ P(Z < 0.35) = 0.6368 $$

Calculate area between the z-scores

Using the Normal Distribution knowledge point

$$ P(0.35 < Z < 1.46) = P(Z < 1.46) - P(Z < 0.35) = 0.9279 - 0.6368 = 0.2911 $$

Convert to percentage

Using the Normal Distribution knowledge point

$$ 0.2911 \times 100\% = 29.11\% $$

Answer:

The percent of data between z = 0.35 and z = 1.46 is <blank>29.11</blank>%.
(Round to two decimal places as needed.)