Question

use the sample data and confidence level given below to complete parts (a) through (d)
a drug is used to help prevent blood clots in certain patients. in clinical trials, among 4829 patients treated with
the drug, 115 developed the adverse reaction of nausea. construct a 90% confidence interval for the proportion of
adverse reactions.
a) find the best point estimate of the population proportion p.
0.024
(round to three decimal places as needed.)
b) identify the value of the margin of error e.
e = 0.004
(round to three decimal places as needed.)
c) construct the confidence interval.
□ < p < □
(round to three decimal places as needed.)

Explanation:

Step1: Recall the confidence interval formula

The confidence interval for a population proportion \(p\) is given by \(\hat{p}-E < p<\hat{p} + E\), where \(\hat{p}\) is the point - estimate and \(E\) is the margin of error.

Step2: Substitute the values

We are given \(\hat{p}=0.024\) and \(E = 0.004\).
Substitute these values into the formula:
\(0.024-0.004

Answer:

\(0.020