Question

use the periodic to write the electron configuration for rubidium (rb) in noble - gas notation. rb: kr s¹

Explanation:

Step1: Determine the noble gas core

Rubidium (Rb) has an atomic number of 37. The noble gas before Rb is Krypton (Kr) which has an atomic number of 36.

Step2: Determine the remaining electrons

Since Rb has 37 electrons and Kr has 36, there is 1 remaining electron. Rubidium is in the 5th period and the s - block. So the remaining electron goes into the 5s orbital.

Answer:

\(5\)