Question

use the periodic table to determine which of the following could be an isotope of indium (in). check all that apply. z = 49, a = 113 n = 64, z = 49 n = 61, a = 113 a = 110, n = 49

Explanation:

Step1: Recall the atomic number of indium

Indium (In) has an atomic number \(Z = 49\). Isotopes of an element have the same atomic number.

Step2: Use the formula \(A=Z + N\)

• For \(Z = 49,A = 113\): Since \(Z = 49\) (matches indium's atomic number), this could be an isotope. Using \(A=Z + N\), we get \(N=A - Z=113 - 49 = 64\).
• For \(N = 64,Z = 49\): \(Z = 49\) (correct atomic number for indium). Using \(A=Z + N\), \(A=49+64 = 113\).
• For \(N = 61,A = 113\): Using \(A=Z + N\), \(Z=A - N=113 - 61=52

eq49\). So this is not an indium isotope.

• For \(A = 110,N = 49\): Using \(A=Z + N\), \(Z=A - N=110 - 49 = 61

eq49\). So this is not an indium isotope.

Answer:

\(Z = 49,A = 113\) and \(N = 64,Z = 49\)