Question

use the formula for $_{n}c_{r}$ to evaluate the given expression.
$_{8}c_{1}$

$_{8}c_{1}=\square$ (type an integer or a simplified fraction.)

Explanation:

Step1: Recall the combination formula

The formula for combination is \(_{n}C_{r}=\frac{n!}{r!(n - r)!}\), where \(n!=n\times(n - 1)\times\cdots\times1\). Here \(n = 8\) and \(r=1\).

Step2: Substitute values into the formula

$$
LATEXBLOCK0
$$

Since \(n!=n\times(n - 1)!\), then \(8! = 8\times7!\).

$$
LATEXBLOCK1
$$

Answer:

\(8\)