Question

use the following balanced equation to answer the questions: 3rb + p → rb₃p how many molecules of rubidium are present?

Explanation:

Step1: Analyze the reactant side

The reactant side of the equation is \(3Rb + P\).

Step2: Count the number of rubidium entities

The coefficient of \(Rb\) is \(3\). In the context of the reaction, each \(Rb\) represents an atom. But if we consider the question about molecules (assuming the problem has a mis - term and actually refers to formula units or atoms in the context of a metal like rubidium which is a monatomic species in this reaction). Since rubidium (\(Rb\)) is a metal and in its elemental form in this reaction, and the coefficient of \(Rb\) is \(3\).

Answer:

\(3\)