Question

use the following balanced equation to answer the questions: 2koh → k₂o + h₂o how many molecules of water are present?

Explanation:

Step1: Analyze the balanced equation

The balanced equation is $2KOH
ightarrow K_2O + H_2O$.

Step2: Determine the coefficient of water

The coefficient of $H_2O$ in the balanced - equation is 1. This means that for every 2 moles of $KOH$ that react, 1 mole of water is produced. In terms of the number of molecules, according to Avogadro's number ($N = n\times N_A$, where $n$ is the number of moles and $N_A$ is Avogadro's number, $N_A=6.022\times 10^{23}$ molecules/mol), if we are just looking at the ratio in the equation, the number of water molecules produced is 1 (in terms of the stoichiometric ratio).

Answer:

1