Question

use the following balanced equation to answer the questions: 2al + 3s → al₂s₃ there are 2 moles of al present. the molar mass of aluminum is 26.98 g/mol. what mass of aluminum is present?

Explanation:

Step1: Recall mass - mole relationship formula

The formula is $m = n\times M$, where $m$ is mass, $n$ is number of moles and $M$ is molar mass.

Step2: Identify given values

We know that $n = 2\ mol$ (moles of Al) and $M=26.98\ g/mol$ (molar mass of Al).

Step3: Calculate the mass

Substitute the values into the formula: $m=2\ mol\times26.98\ g/mol$.
$m = 53.96\ g$

Answer:

$53.96\ g$