use colored pencils to circle the common atoms or compounds in each equation to help you determine the type of reaction it illustrates. use the code below to classify each reaction.
s = synthesis d = decomposition sr = single replacement dr = double replacement
s p + o₂ → p₄o₁₀ mg + o₂ → mgo
hgo → hg + o₂ al₂o₃ → al + o₂
cl₂ + nabr → nacl + br₂ h₂ + n₂ → nh₃
na + br₂ → nabr cucl₂ + h₂s → cus
hgo + cl₂ → hgcl + o₂ c + h₂ → ch₄
kclo₃ → kcl + o₂ s₈ + f₂ → sf₆
bacl₂ + na₂so₄ → nacl + baso₄

Question

Accepted Answer

# Explanation:
## Step1: Recall reaction type definitions
- **Synthesis**: $A + B
ightarrow AB$ (two or more reactants combine to form one product).
- **Decomposition**: $AB
ightarrow A + B$ (one reactant breaks down into two or more products).
- **Single Replacement**: $A+BC
ightarrow AC + B$ (one element replaces another in a compound).
- **Double Replacement**: $AB + CD
ightarrow AD+CB$ (the positive and negative ions of two compounds exchange places).

## Step2: Classify each reaction
- **$Mg + O_{2}
ightarrow MgO$**: Synthesis ($S$) as two reactants ($Mg$ and $O_{2}$) combine to form one product ($MgO$).
- **$HgO
ightarrow Hg + O_{2}$**: Decomposition ($D$) as one reactant ($HgO$) breaks down into two products ($Hg$ and $O_{2}$).
- **$Al_{2}O_{3}
ightarrow Al + O_{2}$**: Decomposition ($D$) as one reactant ($Al_{2}O_{3}$) breaks down into two products ($Al$ and $O_{2}$).
- **$Cl_{2}+NaBr
ightarrow NaCl + Br_{2}$**: Single Replacement ($SR$) as $Cl$ replaces $Br$ in $NaBr$.
- **$H_{2}+N_{2}
ightarrow NH_{3}$**: Synthesis ($S$) as two reactants ($H_{2}$ and $N_{2}$) combine to form one product ($NH_{3}$).
- **$Na + Br_{2}
ightarrow NaBr$**: Synthesis ($S$) as two reactants ($Na$ and $Br_{2}$) combine to form one product ($NaBr$).
- **$CuCl_{2}+H_{2}S
ightarrow CuS + 2HCl$**: Double Replacement ($DR$) (assuming the full reaction, the ions exchange places).
- **$HgO+Cl_{2}
ightarrow HgCl + O_{2}$**: Single Replacement ($SR$) as $Cl$ interacts with $HgO$.
- **$C + H_{2}
ightarrow CH_{4}$**: Synthesis ($S$) as two reactants ($C$ and $H_{2}$) combine to form one product ($CH_{4}$).
- **$S_{8}+F_{2}
ightarrow SF_{6}$**: Synthesis ($S$) as two reactants ($S_{8}$ and $F_{2}$) combine to form one product ($SF_{6}$).
- **$KClO_{3}
ightarrow KCl + O_{2}$**: Decomposition ($D$) as one reactant ($KClO_{3}$) breaks down into two products ($KCl$ and $O_{2}$).
- **$BaCl_{2}+Na_{2}SO_{4}
ightarrow NaCl + BaSO_{4}$**: Double Replacement ($DR$) as the ions exchange places.

# Answer:
$Mg + O_{2}
ightarrow MgO$: $S$
$HgO
ightarrow Hg + O_{2}$: $D$
$Al_{2}O_{3}
ightarrow Al + O_{2}$: $D$
$Cl_{2}+NaBr
ightarrow NaCl + Br_{2}$: $SR$
$H_{2}+N_{2}
ightarrow NH_{3}$: $S$
$Na + Br_{2}
ightarrow NaBr$: $S$
$CuCl_{2}+H_{2}S
ightarrow CuS + 2HCl$: $DR$
$HgO+Cl_{2}
ightarrow HgCl + O_{2}$: $SR$
$C + H_{2}
ightarrow CH_{4}$: $S$
$S_{8}+F_{2}
ightarrow SF_{6}$: $S$
$KClO_{3}
ightarrow KCl + O_{2}$: $D$
$BaCl_{2}+Na_{2}SO_{4}
ightarrow NaCl + BaSO_{4}$: $DR$

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QUESTION IMAGE

Question

Explanation:

Step1: Recall reaction type definitions

Step2: Classify each reaction

Answer: