Question

use the answer bank to complete the names of each compound below:
formula: co₃, c₂h₄, cs₂, ch₄, c₅o₂, c₃s
compound name:
co₃: carbon ?
c₂h₄: ? tetrahydride
cs₂: carbon ?
ch₄: ? tetrahydride
c₅o₂: ? ?
c₃s: ? ?
answer bank: dioxide, dicarbon, trioxide, pentacarbon, monosulfide, carbon, disulfide, tricarbon

Explanation:

Step1: Analyze \( CO_3 \)

The formula is \( CO_3 \). The first part is carbon, and the second part: the subscript of O is 3, so we use "trioxide". So the compound name is carbon trioxide.

Step2: Analyze \( C_2H_4 \)

The formula is \( C_2H_4 \). The first part: subscript of C is 2, so "dicarbon". The second part: subscript of H is 4, and the suffix for hydride with 4 is tetrahydride. So the compound name is dicarbon tetrahydride.

Step3: Analyze \( CS_2 \)

The formula is \( CS_2 \). The first part is carbon. The second part: subscript of S is 2, so "disulfide". So the compound name is carbon disulfide.

Step4: Analyze \( CH_4 \)

The formula is \( CH_4 \). The first part is carbon. The second part: subscript of H is 4, so "tetrahydride" (already given in the table, so we confirm). So the compound name is carbon tetrahydride.

Step5: Analyze \( C_5O_2 \)

The formula is \( C_5O_2 \). The first part: subscript of C is 5, so "pentacarbon". The second part: subscript of O is 2, so "dioxide". So the compound name is pentacarbon dioxide.

Step6: Analyze \( C_3S \)

The formula is \( C_3S \). The first part: subscript of C is 3, so "tricarbon". The second part: subscript of S is 1 (implied), so "monosulfide". So the compound name is tricarbon monosulfide.

Answer:

• \( CO_3 \): carbon trioxide
• \( C_2H_4 \): dicarbon tetrahydride
• \( CS_2 \): carbon disulfide
• \( CH_4 \): carbon tetrahydride
• \( C_5O_2 \): pentacarbon dioxide
• \( C_3S \): tricarbon monosulfide