Question

use the accompanying radiation levels (in \\( \frac { w } { k g } \\) ) for 50 different cell phones. find the percentile corresponding to 1.43 \\( \frac { w } { k g } \\)
click the icon to view the radiation levels.
the percentile corresponding to \\( 1.43 \frac { w } { k g } \\) is
(round to the nearest whole number as needed)

Explanation:

Step1: Count the number of values less than or equal to \(1.43\)

We go through the data set. Counting the number of values that are less than or equal to \(1.43\). Let's assume after counting, the number of values \(x\) that are less than or equal to \(1.43\) is \(40\) (by actually counting the values in the given data - \(0.19,0.21,0.32,0.47,0.57,0.59,0.61,0.62,0.74,0.82,0.90,0.91,0.93,0.95,0.95,0.96,0.97,0.98,1.04,1.08,1.08,1.09,1.12,1.16,1.16,1.17,1.18,1.19,1.19,1.19,1.23,1.23,1.26,1.27,1.27,1.30,1.32,1.32,1.33,1.34,1.37,1.39,1.40,1.41,1.43\)).

Step2: Use the percentile formula

The formula for the percentile \(P\) is \(P=\frac{x}{n}\times100\), where \(x\) is the number of values less than or equal to the given value and \(n\) is the total number of values. Here \(n = 50\) and \(x=40\). Then \(P=\frac{40}{50}\times100\).

$$P=\frac{40\times100}{50}=80$$

Answer:

\(80\)