Question

use the accompanying radiation levels (in \\( \frac { w } { k g } \\) ) for 50 different cell phones. find the percentile corresponding to \\( 1.01 \frac { w } { k g } \\).
click the icon to view the radiation levels.
the percentile corresponding to \\( 1.01 \frac { w } { k g } \\) is
(round to the nearest whole number as needed.)

Explanation:

Step1: Count the number of values less than or equal to \(1.01\)

First, count how many of the 50 values are less than or equal to \(1.01\). By looking at the data:
The values less than or equal to \(1.01\) are: \(0.25,0.28,0.28,0.49,0.59,0.62,0.63,0.65,0.76,0.87,0.89,0.92,0.92,0.93,0.96,0.97,0.99,1.01\). The number of these values \(x = 18\)

Step2: Use the percentile formula

The formula for the percentile \(P\) is \(P=\frac{x}{n}\times100\), where \(x\) is the number of values less than or equal to the given value and \(n\) is the total number of values. Here \(n = 50\) and \(x=18\)

$$P=\frac{18}{50}\times 100=36$$

Answer:

\(36\)