Question

use the accompanying radiation levels (in \\( \frac { w } { k g } \\) ) for 50 different cell phones. find the percentile corresponding to \\( 0.56 \frac { w } { k g } \\)
click icon to view the radiation levels.
the percentile corresponding to \\( 0.56 \frac { w } { k g } \\) is
(round to the nearest whole number as needed.)
radiation levels
0.20 0.21 0.31 0.44 0.56 0.57 0.59 0.66 0.74 0.84
0.87 0.89 0.92 0.95 0.95 0.96 0.99 1.04 1.08 1.09
1.09 1.09 1.09 1.11 1.13 1.14 1.15 1.16 1.17 1.22
1.23 1.24 1.24 1.25 1.25 1.25 1.28 1.30 1.32
1.36 1.36 1.39 1.39 1.42 1.44 1.46 1.50 1.53 1.54

Explanation:

Step1: Count the number of data values less than or equal to \(0.56\)

First, count how many values in the data set are less than or equal to \(0.56\). Looking at the data: \(0.20,0.21,0.31,0.44,0.56\). So there are \(5\) values.

Step2: Calculate the percentile

The formula for the percentile \(P\) is \(P=\frac{\text{Number of values less than or equal to }x}{\text{Total number of values}}\times100\). Here, \(x = 0.56\), the number of values less than or equal to \(x\) is \(n=5\), and the total number of values \(N = 50\). Then \(P=\frac{5}{50}\times100\).

$$P=\frac{5\times100}{50}= 10$$

Answer:

\(10\)