Question

unit 6: chemical reactions - part 4 calculations
below you will find the equation for copper sulfate and sodium bicarbonate. you will need to balance the equation. *some of these may already be balanced. show your work, dont just google it. you are smart and need to be able to do this.
cuso₄ + nahco₃ → cuco₃ + na₂so₄ + co₂ + h₂o
show work here:

Explanation:

Step1: Balance sodium atoms

On the right - hand side, there are 2 sodium atoms in \(Na_2SO_4\). So, we put a coefficient of 2 in front of \(NaHCO_3\) on the left - hand side.
The equation becomes \(CuSO_4+2NaHCO_3
ightarrow CuCO_3 + Na_2SO_4+CO_2 + H_2O\)

Step2: Check other atoms

• Copper (\(Cu\)): 1 atom on both sides.
• Sulfur (\(S\)): 1 atom on both sides.
• Oxygen (\(O\)):
• Left - hand side: \(4\) (from \(CuSO_4\)) \(+2\times3\) (from \(2NaHCO_3\)) \(=4 + 6=10\)
• Right - hand side: \(3\) (from \(CuCO_3\)) \(+4\) (from \(Na_2SO_4\)) \(+2\) (from \(CO_2\)) \(+1\) (from \(H_2O\)) \(=3 + 4+2 + 1=10\)
• Hydrogen (\(H\)): \(2\) (from \(2NaHCO_3\)) on the left - hand side and \(2\) (from \(H_2O\)) on the right - hand side.
• Carbon (\(C\)): \(2\) (from \(2NaHCO_3\)) on the left - hand side (\(1\) in \(CuCO_3\) and \(1\) in \(CO_2\)) on the right - hand side.

Answer:

\(1CuSO_4+2NaHCO_3
ightarrow1CuCO_3 + 1Na_2SO_4+1CO_2 + 1H_2O\)