Question

understand systems of linear equations - instruction - level h
willow are also learning to rock climb. sarita starts 12 feet up and climbs 11 feet each minute. willow starts at the bottom and climbs 15 feet each minute.

when are sarita and willow at the same height at the same time?
after 3 minutes, sarita and willow are at the same height.

use the tables to check your answer.
after 3 minutes, sarita and willow are both blank feet high.

(table for saritas height: minutes (x) 0,1,2,3,4; saritas height (y) 12,23,34,45,56)
(table for willows height: minutes (x) 0,1,2,3,4; willows height (y) 0,15,30,45,60)

Explanation:

Step1: Check Sarita's height at 3 minutes

From Sarita's table, at \( t = 3 \) minutes, her height \( h \) is 34 feet? Wait, no, wait the Sarita's table: let's recheck. Wait the Sarita's height table: at \( t = 0 \), 12; \( t = 1 \), 23? Wait no, maybe I misread. Wait no, the problem says Sarita starts 12 feet up and climbs 11 feet per minute. Wait the table: maybe the table is Sarita's height: at \( t = 0 \), 12; \( t = 1 \), 12 + 11 = 23; \( t = 2 \), 23 + 11 = 34; \( t = 3 \), 34 + 11 = 45? Wait no, the table given in the image: Sarita's Height (h) at \( t = 0 \): 12, \( t = 1 \): 23, \( t = 2 \): 34, \( t = 3 \): 45, \( t = 4 \): 56. Wait Willow's height: at \( t = 0 \): 0, \( t = 1 \): 15, \( t = 2 \): 30, \( t = 3 \): 45, \( t = 4 \): 60. Ah! So at \( t = 3 \) minutes, Sarita's height is 45 (from her table: \( t = 3 \), h = 45) and Willow's height at \( t = 3 \) is 45 (from her table: \( t = 3 \), y = 45). So both are 45 feet high.

Step2: Confirm the height

So after 3 minutes, we check both tables. Sarita's height at \( t = 3 \) is 45, Willow's height at \( t = 3 \) is 45. So the height is 45.

Answer:

45