a. $85\text{ k} = \box\text{ }^\circ\text{c}$
(type an integer or a decimal.)

b. $250\text{ k} = \box\text{ }^\circ\text{c}$
(type an integer or a decimal.)

c. $15\text{ }^\circ\text{c} = \box\text{ k}$
(type an integer or a decimal.)

Question

a. $85\text{ k} = \box\text{ }^\circ\text{c}$
(type an integer or a decimal.)

b. $250\text{ k} = \box\text{ }^\circ\text{c}$
(type an integer or a decimal.)

c. $15\text{ }^\circ\text{c} = \box\text{ k}$
(type an integer or a decimal.)

Accepted Answer

{ "quality": "clear", "question_count": 1, "skills_matched": [ "step_cot", "blank_filling_formatter", "explain_then_answer", "quick" ], "needs_drawing": false, "concepts_used": [], "new_concepts": [ "Temperature Conversion", "Kelvin to Celsius", "Celsius to Kelvin" ], "current_concepts": [ "Temperature Conversion", "Kelvin to Celsius", "Celsius to Kelvin" ] } ## Convert Kelvin to Celsius for part a $$ \begin{aligned} T_{C} &= T_{K} - 273.15 \ T_{C} &= 85 - 273.15 = -188.15 \approx -188 \end{aligned} $$ ## Convert Kelvin to Celsius for part b $$ \begin{aligned} T_{C} &= T_{K} - 273.15 \ T_{C} &= 250 - 273.15 = -23.15 \approx -23 \end{aligned} $$ ## Convert Celsius to Kelvin for part c $$ \begin{aligned} T_{K} &= T_{C} + 273.15 \ T_{K} &= 15 + 273.15 = 288.15 \approx 288 \end{aligned} $$ a. $85\text{ K} =$ $-188.15$ $^\circ\text{C}$ (Type an integer or a decimal.) b. $250\text{ K} =$ $-23.15$ $^\circ\text{C}$ (Type an integer or a decimal.) c. $15^\circ\text{C} =$ $288.15$ $\text{K}$ (Type an integer or a decimal.) { "subject": "Natural Science", "question_type": "Fill-in-the-blank", "knowledge_point": [ "Natural Science", "Physics", "Temperature Conversion" ] }

Sovi.AI - AI Math Tutor

QUESTION IMAGE

Question

Explanation:

Convert Kelvin to Celsius for part a

Convert Kelvin to Celsius for part b

Convert Celsius to Kelvin for part c

Answer: