Question

ty and gajge are both football players who averaged 4 yards per run in yesterdays football game. the statistics from that game are shown in the table. which statement best describes the data? the lengths of tys runs have greater variability because ty had more rushing attempts. tys and gajges runs have the same variability because they both had the same length shortest run. tys and gajges runs have the same variability because they both average 4.0 yards per carry. the lengths of gajges runs have greater variability because there is a greater difference between his longest and shortest runs.

Explanation:

Step1: Calculate the range for Ty

The range is calculated as \( \text{Longest Run}-\text{Shortest Run} \). For Ty, \( 6 - 2=4 \)

Step2: Calculate the range for Gajge

Using the same formula \( \text{Longest Run}-\text{Shortest Run} \). For Gajge, \( 19 - 2 = 17 \)

Step3: Analyze the statements

• The first statement: Variability is not determined by the number of attempts. So, it is wrong.
• The second statement: Same shortest run does not mean same variability. So, it is wrong.
• The third statement: Same average does not mean same variability. So, it is wrong.
• The fourth statement: Since \( 17>4 \), Gajge has a greater range (a measure of variability). So, it is correct.

Answer:

The lengths of Gajge’s runs have greater variability because there is a greater difference between his longest and shortest runs.