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Question
a twelve - sided die with sides labeled 1 through 12 will be rolled once. each number is equally likely to be rolled. what is the probability of rolling a number greater than 7? write your answer as a fraction in simplest form.
Step1: Determine the total number of outcomes
The die has 12 sides, so the total number of possible outcomes \( n(S)=12 \).
Step2: Determine the number of favorable outcomes
The numbers greater than 7 on a 1 - 12 die are 8, 9, 10, 11, 12. So the number of favorable outcomes \( n(E)=5 \).
Step3: Calculate the probability
The probability formula is \( P(E)=\frac{n(E)}{n(S)} \). Substituting the values, we get \( P(E)=\frac{5}{12} \).
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\(\frac{5}{12}\)