Question

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the answer has not been rounded correctly.
the chemical formula for t - butanol is:
$(ch_{3})_{3}coh$
calculate the molar mass of t - butanol.
round your answer to 2 decimal places.
$gcdot mol^{-1}$

Explanation:

Step1: Determine the number of each atom

• Carbon (\(C\)): In \((CH_3)_3COH\), there are \(4\) carbon atoms (\(3\) from \((CH_3)_3\) and \(1\) from \(COH\)).
• Hydrogen (\(H\)): Each \(CH_3\) has \(3\) hydrogens, and there are \(3\) \(CH_3\) groups, so \(3\times3 = 9\) hydrogens from \(CH_3\) groups. Also, there are \(2\) hydrogens from \(COH\) (\(1\) in \(OH\) and \(1\) in \(C - H\) part of \(COH\)), so total \(H\) atoms \(n_H=9 + 2=10\).
• Oxygen (\(O\)): There is \(1\) oxygen atom.

Step2: Use molar mass formula

The molar mass formula is \(M=\sum_{i}n_iM_i\), where \(n_i\) is the number of atoms of type \(i\) and \(M_i\) is the molar mass of atom \(i\).
The molar mass of \(C\) is \(M_C = 12.01\space g/mol\), the molar mass of \(H\) is \(M_H=1.008\space g/mol\), and the molar mass of \(O\) is \(M_O = 16.00\space g/mol\).

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Answer:

\(74.12\space g/mol\)