Question

the trade volume of a stock is the number of shares traded on a given day. the data in the first accompanying table, in millions (so that 6.16 represents 6,160,000 shares traded), represent the volume of a pepsico stock traded for a random sample of 38 trading days in 2018. a second random sample of 38 days in 2018 resulted in the data in the second accompanying table. complete parts (a) through (d).
click here to view the data for sample 1.
click here to view the data for sample 2.

(a) use the data from sample 1 to compute a point estimate for the population mean number of shares traded per day in 2018.
a point estimate for the population mean number of pepsico shares traded per day in 2018 is \\(\square\\) million.
(round to two decimal places as needed.)

Explanation:

Step1: Recall the formula for sample mean

The point estimate for the population mean is the sample mean, denoted as $\bar{x}$. The formula for the sample mean is $\bar{x} = \frac{\sum_{i = 1}^{n} x_{i}}{n}$, where $x_{i}$ are the individual data points and $n$ is the sample size.

Step2: Obtain the data for sample 1

(Assuming we can access the data for sample 1, let's say the data points are $x_1, x_2, \dots, x_{38}$) We need to sum up all these 38 data points and then divide by 38.

Step3: Calculate the sum and then the mean

Let's assume after summing all the data points in sample 1 (say the sum is $S$), then $\bar{x}=\frac{S}{38}$. After performing the calculation (with the actual data), we round to two decimal places.

(Note: Since the actual data for sample 1 is not provided here, but in a typical scenario, if we had the data, for example, if the data points were [let's assume some sample data for illustration, but in reality, we need the actual data from the "Click here to view the data for sample 1" link]. Let's say the data for sample 1 is: 6.16, 5.89, 6.02, 5.93, 6.21, 6.07, 5.98, 6.11, 5.85, 6.05, 6.13, 5.99, 6.08, 5.92, 6.17, 6.03, 5.88, 6.10, 5.95, 6.06, 6.14, 5.97, 6.09, 5.91, 6.18, 6.04, 5.87, 6.09, 5.94, 6.05, 6.12, 5.96, 6.07, 5.90, 6.19, 6.02, 5.86, 6.08.

Summing these up: Let's calculate the sum.

First, group them:

6.16 + 5.89 = 12.05

12.05 + 6.02 = 18.07

18.07 + 5.93 = 24.0

24.0 + 6.21 = 30.21

30.21 + 6.07 = 36.28

36.28 + 5.98 = 42.26

42.26 + 6.11 = 48.37

48.37 + 5.85 = 54.22

54.22 + 6.05 = 60.27

60.27 + 6.13 = 66.4

66.4 + 5.99 = 72.39

72.39 + 6.08 = 78.47

78.47 + 5.92 = 84.39

84.39 + 6.17 = 90.56

90.56 + 6.03 = 96.59

96.59 + 5.88 = 102.47

102.47 + 6.10 = 108.57

108.57 + 5.95 = 114.52

114.52 + 6.06 = 120.58

120.58 + 6.14 = 126.72

126.72 + 5.97 = 132.69

132.69 + 6.09 = 138.78

138.78 + 5.91 = 144.69

144.69 + 6.18 = 150.87

150.87 + 6.04 = 156.91

156.91 + 5.87 = 162.78

162.78 + 6.09 = 168.87

168.87 + 5.94 = 174.81

174.81 + 6.05 = 180.86

180.86 + 6.12 = 186.98

186.98 + 5.96 = 192.94

192.94 + 6.07 = 199.01

199.01 + 5.90 = 204.91

204.91 + 6.19 = 211.1

211.1 + 6.02 = 217.12

217.12 + 5.86 = 222.98

222.98 + 6.08 = 229.06

Now, $n = 38$, so $\bar{x}=\frac{229.06}{38}\approx 6.03$ (this is just an illustration with made - up data. In reality, we need to use the actual data from the sample 1 link).

Answer:

(The answer will be the sample mean of sample 1 rounded to two decimal places. After calculating with the actual data, for example, if the actual sum of sample 1 data is $S$ and $n = 38$, the answer is $\frac{S}{38}$ rounded to two decimal places. If we assume the actual data gives a mean of, say, 6.03 (this is just an example), the answer would be 6.03. But in reality, we need to compute it with the real data from the sample 1 link.)