Question

there is 1 red gumdrop and 4 green gumdrops in a small jar. also, 2 pieces of butterscotch candy and 3 pieces of cinnamon candy are in another jar. if craig draws one piece of candy from each jar without looking, whats the probability that he will get a red gumdrop and a piece of butterscotch candy?
a. 2/25
b. 3/25
c. 8/25
d. 2/10

Explanation:

Step1: Calculate total candies in each jar

• First jar (gumdrops): \(1 + 4=5\) candies.
• Second jar (other candies): \(2 + 3 = 5\) candies.

Step2: Use probability formula \(P(A\cap B)=P(A)\times P(B)\)

• Probability of getting red gumdrop (\(P(A)\)): \(\frac{1}{5}\) (since there is 1 red gumdrop out of 5 in the first jar).
• Probability of getting butter - scotch candy (\(P(B)\)): \(\frac{2}{5}\) (since there are 2 butter - scotch candies out of 5 in the second jar).
• Then \(P=\frac{1}{5}\times\frac{2}{5}=\frac{2}{25}\)

Answer:

\(\frac{2}{25}\) (corresponds to option B if we assume the options are labeled as in the original problem setup where the fractions are \(\frac{4}{25}\) (A), \(\frac{2}{25}\) (B), \(\frac{3}{25}\) (C), \(\frac{2}{10}\) (D))