Question

is there a reaction between lead (ii) nitrate and potassium iodide?* 4 points

yes
no

Explanation:

Step1: Recall solubility rules

According to solubility rules, when lead (II) nitrate (\(Pb(NO_3)_2\)) and potassium iodide (\(KI\)) are mixed in aqueous solution, a double - displacement reaction occurs. The general form of a double - displacement reaction is \(AB + CD
ightarrow AD+CB\). Here, \(A = Pb^{2 +}\), \(B=NO_3^{-}\), \(C = K^{+}\), \(D = I^{-}\). The products are \(PbI_2\) and \(KNO_3\).

Step2: Check solubility of products

The solubility rule for iodides states that most iodides are soluble, but \(PbI_2\) is insoluble. \(KNO_3\) is soluble (all nitrates are soluble and most potassium salts are soluble). Since \(PbI_2\) is insoluble, a precipitation reaction occurs. The chemical equation is \(Pb(NO_3)_2(aq)+2KI(aq)
ightarrow PbI_2(s)+2KNO_3(aq)\)

Answer:

Yes