temperature when 4 different compounds are exposed to room temperature air for over 2 minutes.
what is the likely cause for the difference in evaporation points of the compounds a and d?

| compound | temperature change (°c) | type of imf |
|----------|-------------------------|-------------|
| a | - 12.5 | df |
| b | - 9.2 | df |
| c | - 7.6 | df, dd |
| d | - 4.8 | df, dd, hb |
df – dispersion forces, dd – dipole - dipole, hb – hydrogen bonding

the molecules have different numbers of carbon atoms.

the molecules have different intermolecular forces.

the molecules have different amounts of dispersion forces.

the molecules have different numbers of oxygen

Question

temperature when 4 different compounds are exposed to room temperature air for over 2 minutes.
what is the likely cause for the difference in evaporation points of the compounds a and d?

| compound | temperature change (°c) | type of imf |
|----------|-------------------------|-------------|
| a        | - 12.5                  | df          |
| b        | - 9.2                   | df          |
| c        | - 7.6                   | df, dd      |
| d        | - 4.8                   | df, dd, hb  |
df – dispersion forces, dd – dipole - dipole, hb – hydrogen bonding

the molecules have different numbers of carbon atoms.

the molecules have different intermolecular forces.

the molecules have different amounts of dispersion forces.

the molecules have different numbers of oxygen

Accepted Answer

# Brief Explanations:
Evaporation rate (linked to temperature change) depends on intermolecular forces (IMFs). Compound A has only dispersion forces (DF), while D has DF, dipole-dipole (DD), and hydrogen bonding (HB). Stronger IMFs (like HB in D) reduce evaporation rate, causing a smaller temperature drop. The table directly shows differing IMFs between A and D.

# Answer:
The molecules have different intermolecular forces.

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