Question

it takes 1 molecule of nitrogen and 3 molecules of hydrogen to produce 2 molecules of ammonia using the following formula: 1n₂ + 3h₂ → 2nh₃. identify which combination of molecules will produce ammonia with no leftovers? (1 point) o 8n₂ and 4h₂ o 2n₂ and 6h₂ o 5n₂ and 6h₂ o 4n₂ and 4h₂

Explanation:

Step1: Analyze the reaction ratio

The reaction is $N_2 + 3H_2
ightarrow2NH_3$, which means 1 molecule of $N_2$ reacts with 3 molecules of $H_2$ with no leftovers.

Step2: Check each option

For option 1 ($4N_2$ and $4H_2$), $H_2$ will be the limiting - reactant and there will be $N_2$ leftovers. For option 2 ($5N_2$ and $6H_2$), $H_2$ is the limiting - reactant and there will be $N_2$ leftovers. For option 3 ($2N_2$ and $6H_2$), the ratio of $N_2$ to $H_2$ is $2:6 = 1:3$, so they will react completely with no leftovers. For option 4 ($8N_2$ and $4H_2$), $H_2$ is the limiting - reactant and there will be $N_2$ leftovers.

Answer:

$2N_2$ and $6H_2$