Question

1. the table shows the snacks in mel’s pantry.

snack	amount
chips	3
fruit snack	5

what is the probability that she chooses a fruit snack, puts it back, and then chooses a granola bar?

1. a car dealership has various combinations of

Explanation:

Step1: Calculate total number of snacks

First, we find the total number of snacks by adding the amounts of each snack. The amounts are 4 (Granola Bar), 3 (Chips), and 5 (Fruit Snack). So total = \(4 + 3 + 5 = 12\).

Step2: Probability of choosing a fruit snack

The probability of choosing a fruit snack is the number of fruit snacks divided by total snacks. Number of fruit snacks is 5, so \(P(\text{fruit snack})=\frac{5}{12}\).

Step3: Probability of choosing a granola bar

Since we put the fruit snack back, the total number of snacks remains 12. The number of granola bars is 4, so \(P(\text{granola bar})=\frac{4}{12}=\frac{1}{3}\).

Step4: Probability of both events

Since the events are independent (because we put the snack back), we multiply the two probabilities. So \(P = \frac{5}{12}\times\frac{4}{12}=\frac{5\times4}{12\times12}=\frac{20}{144}=\frac{5}{36}\).

Answer:

\(\frac{5}{36}\)