QUESTION IMAGE
Question
the table represents the temperature of a cup of coffee over time.
temperature of a cup of coffee
| time (minutes) | temperature (degrees fahrenheit) |
|---|---|
| 10 | 180 |
| 20 | 163 |
| 30 | 146 |
| 40 | 131 |
| 50 | 118 |
| 60 | 107 |
which model best represents the data set?
- exponential, because there is a relatively consistent multiplicative rate of change
- exponential, because there is a relatively consistent additive rate of change
- linear, because there is a relatively consistent multiplicative rate of change
- linear, because there is a relatively consistent additive rate of change
Step1: Check additive rate of change
For linear models, the additive rate of change (difference) should be relatively consistent.
- From \(t = 0\) to \(t=10\): \(200 - 180=20\)
- From \(t = 10\) to \(t = 20\): \(180-163 = 17\)
- From \(t = 20\) to \(t=30\): \(163 - 146=17\)
- From \(t = 30\) to \(t = 40\): \(146-131 = 15\)
- From \(t = 40\) to \(t=50\): \(131 - 118=13\)
- From \(t = 50\) to \(t = 60\): \(118-107 = 11\)
The additive rate of change is not consistent, so it is not a linear model.
Step2: Check multiplicative rate of change
For exponential models, the multiplicative rate of change (ratio) should be relatively consistent.
- \(\frac{180}{200}=0.9\)
- \(\frac{163}{180}\approx0.906\)
- \(\frac{146}{163}\approx0.896\)
- \(\frac{131}{146}\approx0.897\)
- \(\frac{118}{131}\approx0.901\)
- \(\frac{107}{118}\approx0.907\)
The multiplicative rate of change is relatively consistent.
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exponential, because there is a relatively consistent multiplicative rate of change