Question

systolic blood pressure levels above 120 mm hg are considered to be high. for the 100 systolic blood pressure levels listed in the accompanying data set, the mean is 120.74000 mm hg and the standard deviation is 14.70698 mm hg. assume that a simple random sample has been selected. use a 0.10 significance level to test the claim that the sample is from a population with a mean greater than 120 mm hg. click the icon to view the data set of systolic blood pressure levels. identify the null and alternative hypotheses. ( h_0: mu = 120 ) ( h_1: mu > 120 ) (type integers or decimals. do not round.) identify the test statistic. (round to two decimal places as needed.)

Explanation:

Step1: Recall the formula for the test statistic in a one - sample z - test (since \(n = 100\geq30\), we can use the z - test)

The formula for the z - test statistic is \(z=\frac{\bar{x}-\mu}{\frac{s}{\sqrt{n}}}\)

Step2: Identify the values of \(\bar{x}\), \(\mu\), \(s\), and \(n\)

We are given that \(\bar{x}=120.7400\), \(\mu = 120\), \(s = 14.70698\), and \(n = 100\)

Step3: Substitute the values into the formula

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Answer:

The test statistic \(z\approx0.50\)