Question

susie calculated the probability of choosing an even number from a list of test grades to be $\frac{5}{18}$. what is the probability of choosing an odd number?
a. $\frac{1}{3}$
b. there is not enough information
c. $\frac{2}{9}$
d. $\frac{13}{18}$

Explanation:

Step1: Use the probability formula

The sum of the probabilities of all possible outcomes is \(1\). Let \(P(\text{even})\) be the probability of choosing an even number and \(P(\text{odd})\) be the probability of choosing an odd number. So \(P(\text{even})+P(\text{odd}) = 1\).

Step2: Substitute the given value

We know that \(P(\text{even})=\frac{5}{18}\). Then \(P(\text{odd})=1 - P(\text{even})\).

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Answer:

D. \(\frac{13}{18}\)