Question

a surveyor is tracking the elevation of a trail at fixed increments of 500 meters. the plot in the de - plane shows the elevation, e, in meters (m) above the starting point versus the distance, d, along the trail from the start in kilometers (km). what is the average rate of change in elevation with respect to distance along the trail in m/km between the starting

Explanation:

Step1: Identify the coordinates

The starting point is \((0,0)\). The point of highest elevation is approximately \((6,130)\).

Step2: Use the average rate of change formula

The formula for average rate of change is \(\frac{\Delta E}{\Delta D}=\frac{E_2 - E_1}{D_2 - D_1}\).
Substitute \(E_1 = 0\), \(D_1=0\), \(E_2 = 130\), \(D_2 = 6\) into the formula: \(\frac{130-0}{6 - 0}=\frac{130}{6}\approx21.67\).

Answer:

\(\frac{130}{6}\approx21.67\) m/km