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suppose the 2006 prices, per ton, of wine grapes for different kinds of…

Question

suppose the 2006 prices, per ton, of wine grapes for different kinds of wine are given in the following table.

varietyprice
merlot$1,400
zinfandel$1,850
pinot noir$1,050
chardonnay$1,350
sauvignon blanc$1,650

what is the mean? (round your answer to two decimal places.)
$

Explanation:

Step1: Sum all prices

Sum the prices: \(1400 + 1400 + 1850 + 1050 + 1350 + 1650\)
\(= 2800 + 1850 + 1050 + 1350 + 1650\)
\(= 4650 + 1050 + 1350 + 1650\)
\(= 5700 + 1350 + 1650\)
\(= 7050 + 1650 = 8700\)

Step2: Calculate the mean

There are 6 data points. Mean \(= \frac{\text{Sum}}{\text{Number of data points}} = \frac{8700}{6}\)
\(= 1450.00\) (rounded to two decimal places)

Answer:

\(1450.00\)