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in a study of cell phone usage and brain hemispheric dominance, an inte…

Question

in a study of cell phone usage and brain hemispheric dominance, an internet survey was e - mailed to 6977 subjects randomly selected from an online group involved with ears. there were 1349 surveys returned. use a 0.01 significance level to test the claim that the return rate is less than 20%. use the p - value method and use the normal distribution as an approximation to the binomial distribution. identify the null hypothesis and alternative hypothesis. a. $h_{0}:p > 0.2$ $h_{1}:p = 0.2$ b. $h_{0}:p < 0.2$ $h_{1}:p = 0.2$ c. $h_{0}:p = 0.2$ $h_{1}:p > 0.2$ d. $h_{0}:p = 0.2$ $h_{1}:p < 0.2$ e. $h_{0}:p
eq0.2$ $h_{1}:p = 0.2$ f. $h_{0}:p = 0.2$ $h_{1}:p
eq0.2$

Explanation:

Step1: Understand the null and alternative hypothesis concepts

The null hypothesis \(H_0\) is a statement of equality. The alternative hypothesis \(H_1\) is the claim we are trying to find evidence for.

Step2: Analyze the claim

The claim is that the return rate \(p\) is less than \(20\%=0.2\). The null hypothesis is the statement of no change or equality, so \(H_0: p = 0.2\). The alternative hypothesis is the claim we test, so \(H_1: p<0.2\)

Answer:

D. \(H_0: p = 0.2\), \(H_1: p<0.2\)