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the students in marys math class recorded the dimensions of their bedro…

Question

the students in marys math class recorded the dimensions of their bedrooms in a frequency table. bedroom areas area (sq. ft) number of bedrooms 60≤a<80 4 80≤a<100 6 100≤a<120 5 120≤a<140 3 140≤a<160 1 create a histogram to represent the data. which statement is most likely true about the mean and the median of the data? the histogram is right - skewed, so the mean is less than the median. the histogram is right - skewed, so the mean is greater than the median. the histogram is left - skewed, so the mean is less than the median. the histogram is left - skewed, so the mean is greater than the median.

Explanation:

Step1: Understand skewness - mean - median relationship

In a right - skewed distribution, the tail is on the right side. The few large values in the right - tail pull the mean towards them, making the mean greater than the median. In a left - skewed distribution, the tail is on the left side and the few small values in the left - tail pull the mean towards them, making the mean less than the median.

Step2: Determine the skewness of the data

Looking at the frequency table, as the area increases, the frequency first increases and then decreases, and the last class ($140\leq A<160$) has the lowest frequency. This indicates a right - skewed distribution.

Step3: Relate skewness to mean and median

Since it is a right - skewed distribution, the mean is greater than the median.

Answer:

The histogram is right - skewed, so the mean is greater than the median.