Question

step 1 add the scores. 76 + 62 + 94 + 80 = 312 step 2 divide the sum of the scores by 4. 312 ÷ 4 = 78 step 3 add the differences between the mean and each score. (76 - 78) + (62 - 78) + (94 - 78) + (80 - 78) = 0 step 4 divide by 4. 0/4 = 0 in which step did souta make the first error? step 1 step 2 step 3 step 4

Explanation:

Step1: Calculate the sum of scores

$$76 + 62+94 + 80=312$$

Step2: Calculate the mean

$$312\div4 = 78$$

Step3: Calculate the sum of differences between the mean and each score

$$(76 - 78)+(62 - 78)+(94 - 78)+(80 - 78)$$
$$=-2-16 + 16+2$$
$$=0$$

Step4: Analyze the error - variance calculation

The formula for variance is \(\frac{\sum_{i = 1}^{n}(x_{i}-\bar{x})^{2}}{n}\), not \(\frac{\sum_{i = 1}^{n}(x_{i}-\bar{x})}{n}\). So the first error is in Step 4.

Answer:

Step 4