Question

the solubility in acetonitrile of molecular compound m is measured and found to be 47.1 g/l at 20. °c. calculate the volume of a saturated solution of m in acetonitrile that would contain 45.0 g of m at this temperature. be sure your answer has the correct unit symbol and number of significant digits.

Explanation:

Step1: Set up the proportion

Let \( V \) be the volume of the solution. We know that solubility \( S=\frac{m}{V} \), where \( S = 47.1\frac{g}{L} \) and \( m = 45.0g \). Rearranging for \( V \), we get \( V=\frac{m}{S} \).

Step2: Substitute the values

Substitute \( m = 45.0g \) and \( S = 47.1\frac{g}{L} \) into the formula: \( V=\frac{45.0g}{47.1\frac{g}{L}} \).

Step3: Calculate the volume

\( V=\frac{45.0}{47.1}L\approx0.955L \) (rounded to three significant digits as 45.0 has three significant digits and 47.1 has three significant digits).

Answer:

\( 0.955L \)