Question

a single die is rolled twice. the 36 equally - likely outcomes are shown to the right.
find the probability of getting two numbers whose sum exceeds 19.
the probability of getting two numbers whose sum exceeds 19 is (type an integer or a simplified fraction)

Explanation:

Step1: Determine the maximum sum of two dice rolls

The maximum number on a single die is \(6\). When rolling two dice, the maximum sum is \(6 + 6=12\).

Step2: Compare the maximum sum with the target sum

Since \(12<19\), there are \(0\) outcomes where the sum of the two - dice rolls exceeds \(19\).

Step3: Calculate the probability

The probability formula is \(P(A)=\frac{n(A)}{n(S)}\), where \(n(A)\) is the number of favorable outcomes and \(n(S)\) is the number of all possible outcomes. Here, \(n(A) = 0\) and \(n(S)=36\). So \(P=\frac{0}{36}\)

Answer:

\(0\)