Question

select the correct answer.
which of the following choices represents a balanced chemical equation?
a. ( mathrm{ca}_{3}left(mathrm{po}_{4}
ight)_{2}+6 mathrm{sio}_{2}
ightarrow mathrm{p}_{4} mathrm{o}_{10}+3 mathrm{casio}_{3} )
b. ( 2 mathrm{ca}_{3}left(mathrm{po}_{4}
ight)_{2}+6 mathrm{sio}_{2}
ightarrow mathrm{p}_{4} mathrm{o}_{10}+6 mathrm{casio}_{3} )
c. ( 2 mathrm{ca}_{3}left(mathrm{po}_{4}
ight)_{2}+3 mathrm{sio}_{2}
ightarrow 2 mathrm{p}_{4} mathrm{o}_{10}+2 mathrm{casio}_{3} )
d. ( 3 mathrm{ca}_{3}left(mathrm{po}_{4}
ight)_{2}+2 mathrm{sio}_{2}
ightarrow mathrm{p}_{4} mathrm{o}_{10}+4 mathrm{casio}_{3} )

Explanation:

Step1: Count atoms in reactants

• For \(Ca\): \(2\times3 = 6\) (from \(2Ca_3(PO_4)_2\))
• For \(P\): \(2\times2 = 4\) (from \(2Ca_3(PO_4)_2\))
• For \(O\): \(2\times(4\times2)+6\times2 = 16 + 12=28\) (from \(2Ca_3(PO_4)_2\) and \(6SiO_2\))
• For \(Si\): \(6\times1 = 6\) (from \(6SiO_2\))

Step2: Count atoms in products

• For \(Ca\): \(6\times1 = 6\) (from \(6CaSiO_3\))
• For \(P\): \(4\times1 = 4\) (from \(P_4O_{10}\))
• For \(O\): \(10+(6\times3)=10 + 18 = 28\) (from \(P_4O_{10}\) and \(6CaSiO_3\))
• For \(Si\): \(6\times1 = 6\) (from \(6CaSiO_3\))

Since the number of each type of atom is the same on both sides of the equation in option B, it is a balanced chemical equation.

Answer:

B. \(2Ca_3(PO_4)_2 + 6SiO_2 \to P_4O_{10} + 6CaSiO_3\)