Question

select the correct answer.
at michaels school, 38% of the students have a pet dog and 24% of the students have a pet cat. michael found that 11% of the students had
both a pet dog and a pet cat.
what is the probability that a randomly chosen student at michaels school will have a pet dog or a pet cat?
a. 40%
b. 62%
c. 51%
d. 83%

Explanation:

Step1: Use the formula for the probability of \(A\cup B\)

The formula for \(P(A\cup B)=P(A)+P(B)-P(A\cap B)\). Let \(A\) be the event that a student has a pet - dog and \(B\) be the event that a student has a pet - cat.
We are given that \(P(A) = 38\%\), \(P(B)=24\%\), and \(P(A\cap B)=11\%\).

Step2: Substitute the values into the formula

Substitute the values into \(P(A\cup B)=P(A)+P(B)-P(A\cap B)\).

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Answer:

C. \(51\%\)